(3x^2-(1/x))^9

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Solution for (3x^2-(1/x))^9 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x^2-(1/x))^9 = 0

(3*x^2-x^-1)^9 = 0

3*x^2-x^-1 = 0

x^-1*(3*x^3-1) = 0

3*x^3 = 1 // : 3

x^3 = 1/3

x^3 = 1/3 // ^ 1/3

x = (1/3)^(1/3)

x^-1*(x-(1/3)^(1/3)) = 0

(x^-1)^9*(x-(1/3)^(1/3))^9 = 0

( x-(1/3)^(1/3) )

x-(1/3)^(1/3) = 0 // + (1/3)^(1/3)

x = (1/3)^(1/3)

( x^-1 )

1*x^-1 = 0 // : 1

x^-1 = 0

x należy do O

x in { (1/3)^(1/3), (1/3)^(1/3), (1/3)^(1/3), (1/3)^(1/3), (1/3)^(1/3), (1/3)^(1/3), (1/3)^(1/3), (1/3)^(1/3), (1/3)^(1/3) }

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